Showing posts with label bernadettet. Show all posts
Showing posts with label bernadettet. Show all posts

Sunday, May 16, 2010

Conjugate Acids and Conjugate Bases

Friday may 14, 2010

We went over the booklet Acid & Bases pg 3- 12. Then we were given a worsheet to work on the first page - Acids & Bases Project Assignment I, indentify the acid, base, conjugate acid(ca), & conjugate base(cb).
Answers:
1.a) acid + base <---> ca + cb
b) acid + base <---> ca + cb
c) base + acid <---> ca + cb
d) base + acid <---> ca + cb
e) acid + base <---> cb + ca

2. write the equation for the reaction of each of the following with water.Indicate wether the ion or molecule is an acid and base. Which one of these are arrhenius acid/bases and which are Bronsted-Lowry acids/bases?
e.g. HBr + H2O <--->H3O+ + Br- , Bronsted - Lowry & Arrhenius Acid
Answers:
2. a) <--->C3H3O2- + H3O+ Arrhenius Acid & Bronsted - Lowry
b) <--->HS- + OH- Bronsted - Lowry Base
c) <--->HSe+ + OH- Bronsted - Lowry Base
d) <---> H2CO3 + OH- Arrhenius Acid & Bronsted - Lowry

Homework for this weekend:
- finish the Next page of the woorksheet Acids & Bases Woorksheet 2 Question 1 & 2, hand in for monday.
- also the foldables (Arrhenius, Bronsted - Lowry , Lewis) follow the rubric for foldables to get a perfect mark this is also hand in for monday.

& the next scribe will be: julien:)

Monday, March 1, 2010

Redox

Today, Ms. K went over the Rules for Determining Oxidation Numbers, we also went over the homework that was assigned for us on Friday. The worksheet question 1-4: Assigning Oxidation Numbers -- Practice.


Oxidation - involves an increase in oxidation
Reduction - involves a decrease in oxidation #

We also learn, how to indicate whether or not the reaction is a Redox reaction

Example of Reduction:
0 +1+5 -2--------> 0 +2 +5 -2
Cu + AgNO3------->Ag + Cu(NO3)

- Ag gain 1 electrons (Reduction)
- Cu loss of 2 electrons (Oxidation)

& we were asked to work on our yellow Booklet on page 21 question #2-17, for tomorrow.
- the next scribe will be
JulieAnneNavea:)